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Sum of roots, product of roots etc. of some polynomial

 
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Saurabh123



Joined: 28 Jun 2006
Posts: 4
Location: Fbd

PostPosted: Tue Jul 04, 2006 12:28 pm    Post subject: Sum of roots, product of roots etc. of some polynomial Reply with quote

Hi guys,

we know that for a quadratic eqn, ax^2+bx+c=0,
sum of roots = -b/a, product of roots = c/a

What bt for a cubic eqn?? ax^3+bx^2+cx+d=0

and in particular how to find
-sum,
-product taken 2 roots at a time
-product taken 3 roots at a time.....and other such things
for a general eqn. ax^n+bx^n-1+cx^n-2+.....+g=0

thnx,
Saurabh
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Saurabh123



Joined: 28 Jun 2006
Posts: 4
Location: Fbd

PostPosted: Wed Jul 05, 2006 10:25 am    Post subject: Re: Sum of roots, product of roots etc. of some polynomial Reply with quote

Hi,

koi to reply karo!!!
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CZ@@@H@@@R
Serious about CAT


Joined: 14 Jan 2006
Posts: 64

PostPosted: Thu Jul 06, 2006 2:44 pm    Post subject: Sum of roots, product of roots etc. of some polynomial Reply with quote

Quote:


Hi guys,

we know that for a quadratic eqn, ax^2+bx+c=0,
sum of roots = -b/a, product of roots = c/a

What bt for a cubic eqn?? ax^3+bx^2+cx+d=0

and in particular how to find
-sum,
-product taken 2 roots at a time
-product taken 3 roots at a time.....and other such things
for a general eqn. ax^n+bx^n-1+cx^n-2+.....+g=0

thnx,



an x^n+ an-1 x^n-1 + an-2 x^n-2 + .. a1 x ...+ a0 = 0

n, n-1, .... are subscripts to a

Sum(one root at a time) = - an-1 / an
Sum(Two roots at a time) = an-2 / an
.
.
.
Sum(k roots at a time) = (-1)^k an-k / an
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g2



Joined: 01 Aug 2006
Posts: 4

PostPosted: Thu Aug 03, 2006 10:04 pm    Post subject: Reply with quote

hi
i just know that the no. of solution we have for an equation like that is simply the power of its 1st variable like----------
a x^3+bx^2+cx+d=0 then the no. of solution will be 3 and so on.....
i think u have asked that only
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kunalkapse



Joined: 08 Jul 2006
Posts: 4

PostPosted: Mon Aug 07, 2006 2:40 am    Post subject: reply Reply with quote

hi saurabh
i m here ro help u out
let us suppose a equation
a.x(pow n) + b.x(pow n-1)+c.x(n-2)+d.x(n-3)+c=0
then
sum of roots taken one at a time= -coeff of x(pow n-1)/coeff of x(pow n)
sum of roots taken two at a time=coeff of x(n-2)/coeff of x(pow n)
sum of roots taken three at a time= -coeff of x(n-3)/coeff of x(pow n)
u notice the pattern?alternate signs?
ok
now product of roots=(+or-)coeff of constant term/coeff of x(pow n)
sign would be positive for an even degree equation and negative for odd degree equation.
i thing i cleared ur doubts
say thanks!!!!!!!!!!!!!!!!!
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