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sumitsingh
Been around a while
Joined: 22 Jun 2005
Posts: 46
Location: lucknow
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 Posted: Fri Jul 01, 2005 2:03 pm Post subject: equation problem |
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there are 10 child in class all have diff no of choclates . if 1 st distribute its choclate in remaining 9 , in such a way all other has twice as much as they initially have and 1 st has 1 choclate still with him . and if 10 th take one from each of other 9 he has 4 less than what first child initially has , now what is the total no of choclate with child from 2-9 initially .  |
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shaji
Serious about CAT
Joined: 22 May 2005
Posts: 71
Location: UK
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| Posted: Sat Jul 02, 2005 1:33 pm Post subject: Re: equation problem |
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| sumitsingh wrote: | | there are 10 child in class all have diff no of choclates . if 1 st distribute its choclate in remaining 9 , in such a way all other has twice as much as they initially have and 1 st has 1 choclate still with him . and if 10 th take one from each of other 9 he has 4 less than what first child initially has , now what is the total no of choclate with child from 2-9 initially . |
Hi;
Let
a,b,c, d........j be the chocolates with the 10 children respectively from first to the tenth.
a=1+b+c+.......j.
j+9=a-4.
Therfore;
b+c+-------i=12
The problem however does not satify the condition that each each child has a different number of chocolates. For this to be true, the minimum for the eight children under question has be 36.
Please review original question.
Shaji |
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sumitsingh
Been around a while
Joined: 22 Jun 2005
Posts: 46
Location: lucknow
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| Posted: Mon Jul 04, 2005 10:11 am Post subject: |
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Hi
thanks buddy i got the question wrong , initially i have not thonk abt it
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montex
Joined: 18 Jun 2005
Posts: 23
Location: New Delhi
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| Posted: Sat Jul 16, 2005 2:11 pm Post subject: here is the answer |
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let the no. of chocs with first boy be----- I
let the no. of chocs with the tenth boy be ------------L
let the no of chocs from 2 to 9 boys be---------------T
so , I=T+L+1
L+9=I-4
adding both these equations we get
I+L+9=T+L+I-3
= T=12 is the answer
hope this is clear enough 
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shaji
Serious about CAT
Joined: 22 May 2005
Posts: 71
Location: UK
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| Posted: Sat Jul 16, 2005 7:35 pm Post subject: Re: here is the answer |
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| montex wrote: | let the no. of chocs with first boy be----- I
let the no. of chocs with the tenth boy be ------------L
let the no of chocs from 2 to 9 boys be---------------T
so , I=T+L+1
L+9=I-4
adding both these equations we get
I+L+9=T+L+I-3
= T=12 is the answer
hope this is clear enough
bye |
Hi;
Please appreciate that if 8 children have 12 chocolates among them, then the condition that no 2 children will have the same number of chocolates is NOT satisfied.
This is the observation that I had made above.
Regards;
Shaji |
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