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A problem on Time Speed Distance : MBA Entrance Math - Quant Doubts

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 Post subject: A problem on Time Speed Distance
PostPosted: Tue Oct 04, 2005 11:01 pm 
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Joined: Tue Oct 04, 2005 10:58 pm
Posts: 1
Hi Friends ,

Try this !

In a Kilometre race , if A gives B a 40 m start ,A wins by 19 sec .But if A gives a 30 sec start, B wins by 40 m . Find the time taken by B to run 5000 m .


a. 150 s
b. 450 s
c. 750 s
d. 825 s


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 Post subject: Answer found for time and dist. problem
PostPosted: Fri Oct 07, 2005 7:28 pm 
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Joined: Thu Oct 06, 2005 12:48 am
Posts: 3
Location: mumbai
well Shrikant i got the answer but its got quiet a lot of calculation.

let the time the time required by B to finish first race be x,and the dist. covered is 960 hence speed B's speed is 960/x

now time required by A to finish first race is (x-19) ,and the dist. covered is 1000m hence speed A's speed is 1000/(x-19)

acc. to second statement Bgets a head start of 30 sec therefore the dist. covered in 30 sec is 960*3/x therefore the dist. covered by B in second race after 30 sec is 1000-(960*3/x). since the speed is known we can determine the time required by B to finish the race.this time is given by,

[1000-(960*3/x)] / (960/x).....(dist/speed)........EQN1

this is the time required by A to run 960m..... ( B wins by 40m)

thus EQN1*A's speed=960
solving this u'll get the required answer as 750

A's speed=1000/(x-19)


P.S: dont mulltiply x with 5 ... (x is the time required to run 960m and not 1000m)


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